document.write( "Question 157683: What is the approximate surface area of the observatory if the radius is 10 ft and its altitude measures 24 ft \n" ); document.write( "
Algebra.Com's Answer #116184 by Fombitz(32388)\"\" \"About 
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I'm assuming the building is a cylinder with a hemisphere roof.
\n" ); document.write( "The cylinder surface are is the perimeter of the circle (hemisphere) multiplied by the height of the cylinder.
\n" ); document.write( "The height of the cylinder is the total height minus the hemisphere radius.
\n" ); document.write( "\"SA%5Bc%5D=2%2Api%2AR%2A%28H%5Bt%5D-R%29\"
\n" ); document.write( "\"SA%5Bc%5D=2%2Api%2A10%2A%2824-10%29\"
\n" ); document.write( "\"SA%5Bc%5D=2%2Api%2A10%2A%2814%29\"
\n" ); document.write( "\"SA%5Bc%5D=280%2Api\"
\n" ); document.write( "The surface area of the hemisphere is 1/2 the surface area of a sphere with radius 10 ft.
\n" ); document.write( "\"SA%5Bs%5D=%281%2F2%29%2A4%2Api%2AR%5E2\"
\n" ); document.write( "\"SA%5Bs%5D=2%2Api%2A10%5E2\"
\n" ); document.write( "\"SA%5Bs%5D=200%2Api\"
\n" ); document.write( "THe total surface is the sum of these two.
\n" ); document.write( "\"SA%5Bt%5D=SA%5Bc%5D%2BSA%5Bs%5D\"
\n" ); document.write( "\"SA%5Bt%5D=280%2Api%2B200%2Api\"
\n" ); document.write( "\"SA%5Bt%5D=480%2Api\"
\n" ); document.write( "or approximately
\n" ); document.write( "\"SA%5Bt%5D=1508\"
\n" ); document.write( "1508 sq. ft.
\n" ); document.write( "
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