document.write( "Question 22523: Hi i'm stuck with the following problem can anyone help\r
\n" ); document.write( "\n" ); document.write( "If i1=0.02sin(ωt) and i2 =0.032cos(ωt-π/3)\r
\n" ); document.write( "\n" ); document.write( "Determine an expression for output current i=i1+i2 in the form R sin(ωt+ά)
\n" ); document.write( "and thus state the its amplitude and phase angle \n" ); document.write( "
Algebra.Com's Answer #11618 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
I1 = 0.02Sin(wt)
\n" ); document.write( " I2 = 0.032Cos(wt-pi/3) = 0.032{Cos(wt)Sin(pi/3)+Sin(wt)Cos(pi/3)} =
\n" ); document.write( " I2 = 0.032{0.866Cos(wt)+0.5Sin(wt)} = 0.028Cos(wt)+0.016Sin(wt) \r
\n" ); document.write( "\n" ); document.write( " I1+I2 = 0.02Sin(wt)+0.028Cos(wt)+0.016Sin(wt)
\n" ); document.write( " = 0.036Sin(wt)+0.028Cos(wt)
\n" ); document.write( " NOW MULTIPLY AND DIVIDE WITH SQUARE ROOT OF (0.036^2+0.028^2)= 0.0456
\n" ); document.write( " LET Sin(a)=0.028/0.0456…SO THAT…Cos(a)=0.036/0.0456…HENCE WE GET
\n" ); document.write( " I1+I2 = Sin(wt)Cos(a)+Cos(a)Sin(wt) = Sin(wt+a)…..WITH A BEING ARC SIN (0.028/0.0456)
\n" ); document.write( " OR …Sin(a) = (0.028/0.0456)
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