document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157581>Question 157581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> base of temple is a rectangle with a perimeter of 300m.  the area of the base is 4400m.  what are the dimensions of the base?\r<BR>\n" );
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document.write( "all i have is<BR>\n" );
document.write( "l+w=perimeter<BR>\n" );
document.write( "lxw=4400 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116125 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L*W=4400<BR>\n" );
document.write( "L=4400/W<BR>\n" );
document.write( "2L+2W=300<BR>\n" );
document.write( "2(4400/W)+2W=300<BR>\n" );
document.write( "(8800+2W*W)/W=300<BR>\n" );
document.write( "8800+2W^2=300W<BR>\n" );
document.write( "2W62-300W+8800=0<BR>\n" );
document.write( "2(W^2-150W+4400)<BR>\n" );
document.write( "2(W-110)(W-40)=0<BR>\n" );
document.write( "W-110=0<BR>\n" );
document.write( "W=110 ANSWER FOR THE WIDTH & LENGTH=40<BR>\n" );
document.write( "OR LENGTH=40 & WIDTH=10<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "40*110=4400<BR>\n" );
document.write( "4400=4400<BR>\n" );
document.write( "2*110+2*40=300<BR>\n" );
document.write( "220+80=300<BR>\n" );
document.write( "300=300 </SPAN>\n" );
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