document.write( "Question 157585: Carol invested $12,000 for one year, part at 10% annual interest and the balance at 12% annual interest. After the one year she earned $1420 in interest. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #116121 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .12X+.10(12,000-X)=1,420 \n" ); document.write( ".12X+1,200-.10X=1,420 \n" ); document.write( ".02X=1,420-1,200 \n" ); document.write( ".02X=220 \n" ); document.write( "X=220/.02 \n" ); document.write( "X=11,000 INVESTED @ 12% \n" ); document.write( "12,000-11,000=1,000 INVESTED @ 10% \n" ); document.write( "PROOF: \n" ); document.write( ".12*11,000+.10*1,000=1.420 \n" ); document.write( "1,320+100=1,420 \n" ); document.write( "1,420=1,420 \n" ); document.write( " |