document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157566>Question 157566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four times the measure of the complement of an angle is 12 more than twice the difference of the measures of its supplement and its complement. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116106 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Four times the measure of the complement of an angle is 12 more than twice the difference of the measures of its supplement and its complement. Find the measure of each angle.<BR>\n" );
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document.write( "Let x = measure of angle<BR>\n" );
document.write( "90-x = complement<BR>\n" );
document.write( "180-x = supplement<BR>\n" );
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document.write( "4(90-x) = 2((180-x)-(90-x))+12<BR>\n" );
document.write( "360-4x = 2(180-x-90+x)+12<BR>\n" );
document.write( "360-4x = 2(90)+12<BR>\n" );
document.write( "360-4x = 180+12<BR>\n" );
document.write( "360-4x = 192<BR>\n" );
document.write( "-4x = -168<BR>\n" );
document.write( "x = 42 deg (measure of angle)<BR>\n" );
document.write( "90-x = 90-42 = 48 deg (measure of complement)<BR>\n" );
document.write( "180-x = 180-42 = 138 deg (measure of supplement)<BR>\n" );
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