document.write( "Question 22405: Here is another i do not understand:
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document.write( "-3x+8y=10
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document.write( "5x+6y=80
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document.write( " Here i have to solve each system by using elimination, and check my solution. \n" );
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Algebra.Com's Answer #11606 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! Solving by elimination means you need to eliminate one of the variables to solve for the other. \n" ); document.write( "So lets start by eliminating the x; \n" ); document.write( "-3x+8y=10 \n" ); document.write( "5x+6y=80 \n" ); document.write( "To eliminate the x we need to make both numbers opposite so they cancel out, so we will need to multiply each equation by the number that does that. \n" ); document.write( "(5)-3x+8y=10 \n" ); document.write( "-15x+40y=50 - eq.1 \n" ); document.write( "(3)5x+6y=80 \n" ); document.write( "15x+18y=240 - eq.2 \n" ); document.write( "Now we will add one equation to the other; \n" ); document.write( "-15x+40y=50 \n" ); document.write( " 15x+18y=240 \n" ); document.write( "------------- \n" ); document.write( " 58y=290 \n" ); document.write( " y=5 \n" ); document.write( "Now that we have y, we will plug that into the equation to solve for x; \n" ); document.write( "5x+6(5)=80 \n" ); document.write( "5x+30=80 \n" ); document.write( "5x=50 \n" ); document.write( "x=10 \n" ); document.write( "Hope you understand \n" ); document.write( "=) \n" ); document.write( " |