document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157456>Question 157456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FIND THE SIDE OF A SQUARE WHOSE DIAGONAL IS 5 CM </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116027 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIND THE SIDE OF A SQUARE WHOSE DIAGONAL IS 5 CM.\r<BR>\n" );
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document.write( "Let s = side of this square\r<BR>\n" );
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document.write( "The diagonal is our hypotenuse and any two sides can be the two legs.\r<BR>\n" );
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document.write( "We use the Pythagorean Theorem to find s.\r<BR>\n" );
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document.write( "s^2 + s^2 = 5^2\r<BR>\n" );
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document.write( "2s^2 = 25\r<BR>\n" );
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document.write( "Divide both sides by s.\r<BR>\n" );
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document.write( "s^2 = 25/2\r<BR>\n" );
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document.write( "Take the square root of both sides.\r<BR>\n" );
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document.write( "s = sqrt{25/2}\r<BR>\n" );
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document.write( "We can house the numerator and denominator into their own radical symbol.\r<BR>\n" );
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document.write( "s = sqrt{25}/sqrt{2}\r<BR>\n" );
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document.write( "s = 5/sqrt{2}\r<BR>\n" );
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document.write( "We rationalize the denominator because a radical is never accepted in the denominator.\r<BR>\n" );
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document.write( "Doing so, our final answer is:\r<BR>\n" );
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document.write( "side of this square = 5(sqrt{2})/2....This is read: \"Five times the square root of two divided by two.\"\r<BR>\n" );
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document.write( "Is this clear? </SPAN>\n" );
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