document.write( "Question 157424: a certain investment fund multiplies the value of an investment by 4 every year. Thus, after n years, the value of the investment is multiplied by 4^n. how many years will it take for the value of the investment to be multiplied by 256? \n" ); document.write( "
Algebra.Com's Answer #116019 by gonzo(654)\"\" \"About 
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n = 4
\n" ); document.write( "4^4 = 256.
\n" ); document.write( "n = 1, multiply by 4
\n" ); document.write( "n = 2 multiply by 4 again = 16
\n" ); document.write( "n = 3 multiply by 4 again = 64
\n" ); document.write( "n = 4 multiply by 4 again = 256
\n" ); document.write( "solved by using logarithms although n was so small it could have been done by simply working up each year as shown above.
\n" ); document.write( "n = log of 256 to the base 4 is the same as n = log of 256 to the base 10 divided by log of 4 to the base 10.
\n" ); document.write( "this allows the calculator to be used.
\n" ); document.write( "log of 256 to the base 10 = 2.408........
\n" ); document.write( "log of 4 to the base 10 = .602..................
\n" ); document.write( "n = log of 256 to the base 10 / log of 4 to the base 10 = 4
\n" ); document.write( "n = 4
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