document.write( "Question 157326: 3/y=y/(5y-12) \n" ); document.write( "

Algebra.Com's Answer #115982 by checkley77(12844) $\"\"$ $\"About$

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3/y=y/(5y-12) CROSS MULTIPLY
\n" ); document.write( "Y^2=3(5Y-12)
\n" ); document.write( "Y^2=15Y-36
\n" ); document.write( "Y^2-15Y+32=0
\n" ); document.write( "Using the quadratic equation: $\"x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\"$ we get:
\n" ); document.write( "y=(15+-sqrt[-15^2-4*1*32])/2*1
\n" ); document.write( "y=(15+-sqrt[225-128])/2
\n" ); document.write( "y=(15+-sqrt97)/2
\n" ); document.write( "y=(15+-9.9488)/2
\n" ); document.write( "y=(15+9.9488)/2
\n" ); document.write( "y=24.8488/2
\n" ); document.write( "y=12.42 answer.
\n" ); document.write( "y=(15-9.9488)/2
\n" ); document.write( "y=5.0512/2
\n" ); document.write( "y=2.53 answer.
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