document.write( "Question 157305: How many liters of a 70% acid solution are needed to be mixed with 18 liters of a 10% acid solution to get a mixture which is 25% alcohol? \n" ); document.write( "

Algebra.Com's Answer #115944 by checkley77(12844) $\"\"$ $\"About$

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.7x+.1*18=.25(x+18)
\n" ); document.write( ".7x+1.8=.25x+4.5
\n" ); document.write( ".7x-.25x=4.5-1.8
\n" ); document.write( ".45x=2.7
\n" ); document.write( "x=2.7/.45
\n" ); document.write( "x=6 gallons of 70% acid is needed.
\n" ); document.write( "Proof:
\n" ); document.write( ".7*6+.1*18=.25(6+18)
\n" ); document.write( "4.2+1.8=.25*24
\n" ); document.write( "6=6
\n" ); document.write( " \n" ); document.write( "

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