document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157301>Question 157301</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1602773033/algebrahomeworkh>Saxon Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A circle has a diameter with endpoints (-8,-1) and (-3,13). Find the center of the cicle. Find the area of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115935 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (13+1)^2+(-3+8)^2=d^2<BR>\n" );
document.write( "14^2+5^2=d^2<BR>\n" );
document.write( "196+25=d^2<BR>\n" );
document.write( "d^2=221<BR>\n" );
document.write( "d=sqrt221<BR>\n" );
document.write( "d=14.866 is the disstance between these 2 points.<BR>\n" );
document.write( "x midpoint=(-3+8)/2=5/2=2.5<BR>\n" );
document.write( "now we either add 2.5 to -8 or subtract 2.5 from -3<BR>\n" );
document.write( "-8+2.5=-5.5<BR>\n" );
document.write( "-3-2.5=-5.5<BR>\n" );
document.write( "y midpoint=(13+3)/2=16/2=8<BR>\n" );
document.write( "again add to -3 or subtract from 13.<BR>\n" );
document.write( "-3+8=5<BR>\n" );
document.write( "13-8=5<BR>\n" );
document.write( "Thus the midpoint is (-5.5,5)<BR>\n" );
document.write( "Area=2pir^2<BR>\n" );
document.write( "Area=2*3.14(14.866/2)<BR>\n" );
document.write( "Area=6.28*7.433<BR>\n" );
document.write( "Area=46.679  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );