document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157232>Question 157232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you have a bad grass fire with wind that is burning at the rate of .04 acres per second how many acres will burn in 48 hours?  (assuming the rate will not change the entire time)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115924 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.04 acres/sec=0.04 *60acres/min= 2.4 acres/min------(60 sec=1 min)<BR>\n" );
document.write( "2.4 acres/min=2.4*60 acres/hour=144 acres/hour (60 min=1 hour)<BR>\n" );
document.write( "144 acres/hour*48 hours=6912 acres\r<BR>\n" );
document.write( "\n" );
document.write( "CK <BR>\n" );
document.write( "how many seconds in 1 hour? 60*60=3600<BR>\n" );
document.write( "How many seconds in 48 hours? 3600*48=172800<BR>\n" );
document.write( "so, 0.04*172800=6912<BR>\n" );
document.write( "6912=6912\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );