document.write( "Question 157292: -3x+b=6x for x\r
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\n" ); document.write( "\n" ); document.write( "-5a+y=-54 for y
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Algebra.Com's Answer #115918 by midwood_trail(310)\"\" \"About 
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(1) 3x + b = 6x solve for x\r
\n" ); document.write( "\n" ); document.write( "To solve for a variable means to place the letter alone on one side of the equation.\r
\n" ); document.write( "\n" ); document.write( "We need to ISOLATE x.\r
\n" ); document.write( "\n" ); document.write( "Let's begin by subtracting 3x from both side.\r
\n" ); document.write( "\n" ); document.write( "We now have this:\r
\n" ); document.write( "\n" ); document.write( "b = 6x - 3x\r
\n" ); document.write( "\n" ); document.write( "b = 3x\r
\n" ); document.write( "\n" ); document.write( "To find x, divide both sides of the equation by 3.\r
\n" ); document.write( "\n" ); document.write( "b/3 = x....This is the value of x and your answer.\r
\n" ); document.write( "\n" ); document.write( "Do you see that x is left alone on the right side?\r
\n" ); document.write( "\n" ); document.write( "I just solved for x.\r
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\n" ); document.write( "\n" ); document.write( "(2) -5a + y = -54 solve for y\r
\n" ); document.write( "\n" ); document.write( "The same applies here.\r
\n" ); document.write( "\n" ); document.write( "ISOLATE y: put it all alone on one side of the equation.\r
\n" ); document.write( "\n" ); document.write( "To find y, simply add 5a to both sides.\r
\n" ); document.write( "\n" ); document.write( "y = 5a - 54\r
\n" ); document.write( "\n" ); document.write( "Do you see that y is now alone (or ISOLATED) on the left side of the equation?\r
\n" ); document.write( "\n" ); document.write( "That's what it means to solve for a variable, ANY VARIABLE.\r
\n" ); document.write( "\n" ); document.write( "Did you follow?\r
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