document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21670>Question 21670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HI, I have a story problem I'm having a difficult time with, I was wondering if somebody could help me?\r<BR>\n" );
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document.write( "Question: A bag contains 6 red marbles, 9 blue marbles, and 5 green marbles. You withdraw one marble, replace it, and then withdraw another marble. What is the probability that you do NOT pick two green marbles?\r<BR>\n" );
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document.write( "                   thank you,<BR>\n" );
document.write( "                         chris </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11591 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bag contains 6 red marbles, 9 blue marbles, and 5 green marbles. You withdraw one marble, replace it, and then withdraw another marble. What is the probability that you do NOT pick two green marbles?\r<BR>\n" );
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document.write( "SINCE THE MARBLES ARE REPLACED ,WE HAVE ALWAYS SAME NUMBER OF EACH COLOURED MARBLE IN THE BAG.THAT IS PROBABILITY OF DRAWING A PARTICULAR COLOUR MARBLE IS CONSTANT IN EACH PICK.LET US FIND THEM FIRST<BR>\n" );
document.write( "TOTAL MARBLES = 6 RED+9 BLUE+5 GREEN =20<BR>\n" );
document.write( "PROBABILITY OF DRAWING GREEN =PG=5/20=1/4<BR>\n" );
document.write( "PROBABILITY OF DRAWING BLUE.. =PB=9/20<BR>\n" );
document.write( "PROBABILITY OF DRAWING RED =PR=6/20=3/10<BR>\n" );
document.write( "THEY ARE CONSTANT ALWAYS......<BR>\n" );
document.write( "NOW IT IS ASKED THAT WE SHOULD NOT PICK 2 GREENS IN 2 PICKS...SO LET US LIST ALL POSSIBILITIES......<BR>\n" );
document.write( "1ST.GREEN..2ND...BLUE...=PROBABILITY=(1/4)(9/20)<BR>\n" );
document.write( "1ST.GREEN...2ND...RED...=PROBABILITY=(1/4)(3/10)\r<BR>\n" );
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document.write( "1ST.BLUE..2ND....GREEN...=PROBABILITY=(9/20)(1/4)\r<BR>\n" );
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document.write( "1ST.BLUE...2ND....BLUE...=PROBABILITY=(9/20)(9/20)\r<BR>\n" );
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document.write( "1ST.BLUE...2ND....RED...=PROBABILITY=(9/20)(3/10)\r<BR>\n" );
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document.write( "1ST.RED...2ND...GREEN...=PROBABILITY=(3/10)(1/4)\r<BR>\n" );
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document.write( "1ST.RED...2ND...BLUE...=PROBABILITY=(3/10)(9/20)\r<BR>\n" );
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document.write( "1ST.RED...2ND...RED...=PROBABILITY=(3/10)(3/10)<BR>\n" );
document.write( "HENCE FIND EACH OF THE ABOVE AND ADD THEM UP TO GET TOTAL PROBABILITY OF NOT PICKING 2 GREEN MARBLES...ANOTHER EASIER WAY WOULD BE TO FIND PROBABILITY OF DRAWING 2 GREENS AND SUBTRACTING THAT FROM TOTAL PROBABILITY OF 1 TO GET THE PROBABILITY OF NOT DRAWING 2 GREENS...<BR>\n" );
document.write( "THOUGH THIS IS EASIER AND BETTER I DID THE OTHER LONGER WAY TO SHOW YOU THE LOGIC AND METHOD..SO THE ANSWER YOU GET IS <BR>\n" );
document.write( "1ST.GREEN..2ND...GREEN...=PROBABILITY=(1/4)(1/4)=1/16<BR>\n" );
document.write( "HENCE PROBABILITY OF NOT GETTING 2 GREENS IS =1-1/16=15/16\r<BR>\n" );
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document.write( " </SPAN>\n" );
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