document.write( "Question 157251: I am given the zeros (ie. cross x axis at -3 and 4), and told the equation crosses the y axis at 48, how would I make a quadratic equation out of this? \n" ); document.write( "
Algebra.Com's Answer #115896 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! I am given the zeros (ie. cross x axis at -3 and 4), and told the equation crosses the y axis at 48, how would I make a quadratic equation out of this? \n" ); document.write( ". \n" ); document.write( "Since the problem states that the quadratic crosses the x-axis at -3 and 4 we now KNOW two factors of the quadratic. So far, then, we have: \n" ); document.write( "y = (x+3)(x-4) \n" ); document.write( ". \n" ); document.write( "Notice that to determine where a quadratic crosses the y-axis, set x=0 and solve for y: \n" ); document.write( "y = (x+3)(x-4) \n" ); document.write( "y = (0+3)(0-4) \n" ); document.write( "y = (3)(-4) \n" ); document.write( "y = -12 \n" ); document.write( "And, because the problem states that it \"crosses the y axis at 48\"... \n" ); document.write( "To get it to 48, we ask ourself what do we multiply -12 with to get 48? And, the answer is -4. \n" ); document.write( ". \n" ); document.write( "So, now we have: \n" ); document.write( "y=-4(x+3)(x-4) \n" ); document.write( "y=-4(x^2-x-12) \n" ); document.write( "y=-4x^2+4x+48 (this is what they are looking for) \n" ); document.write( ". \n" ); document.write( "Here's the quadratic solution: \n" ); document.write( "
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