document.write( "Question 157209: 1/3(b+12)-1/4(b+12) \n" ); document.write( "

Algebra.Com's Answer #115889 by checkley77(12844) $\"\"$ $\"About$

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1/3(b+12)-1/4(b+12)
\n" ); document.write( "(b+12)/3-(b+12)/4
\n" ); document.write( "[4(b+12)-3(b+12)]/3*4
\n" ); document.write( "[4b+48-3b-36]/12
\n" ); document.write( "(b+12)/12 answer.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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