document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157157>Question 157157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack usually mows his lawn in 6 hours.  Marilyn can mow the same yard in 7 hours.  How much time would it take for them to mow the lawn together.  (simplify your answerr.  Type an integer, proper fraction or mixed number) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115846 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=amount of time it takes them both working together to mow the yard<BR>\n" );
document.write( "Jack mows at the rate of 1/6 yard per hour<BR>\n" );
document.write( "Marilyn mows at the rate of 1/7 yard per hour<BR>\n" );
document.write( "Together they mow at the rate of 1/6 +1/7 or 7/42 + 6/42=13/42 yard per hour<BR>\n" );
document.write( "So, our equation to solve is:<BR>\n" );
document.write( "(13/42)*x=1 (1 yard, that is) multiply each side by 42<BR>\n" );
document.write( "13x=42 divide each side by 13<BR>\n" );
document.write( "x=42/13 or 3 3/13 hour \r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "(1/6)(42/13)=7/13<BR>\n" );
document.write( "(1/7)(42/13)=6/13<BR>\n" );
document.write( "7/13 + 6/13=13/13 or 1 yard\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
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