document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157186>Question 157186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A long-distance runner can run 6 mph downhill, but her speed is cut to 2 mph when she encounters a hill. If she runs the 6 miles uphill and 6 miles downhill, what is her average speed?\r<BR>\n" );
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document.write( "If possible please show the work, i want to understand how to approach the answer. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115842 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "6=6T<BR>\n" );
document.write( "T=6/6<BR>\n" );
document.write( "T=1 HOUR FOR THE DOWN HILL RUN.<BR>\n" );
document.write( "6=2T<BR>\n" );
document.write( "T=6/2<BR>\n" );
document.write( "T=3 HOURS FOR THE UPHILL RUN.<BR>\n" );
document.write( "12=R*(3+1)<BR>\n" );
document.write( "12=4R<BR>\n" );
document.write( "R=12/4<BR>\n" );
document.write( "R=3 MPH IS THE AVERAGE SPEED.<BR>\n" );
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