document.write( "Question 157083: At the football game, your group buys 10 hot dogs and 5 sodas and pays $12.50. Another group of people buys 7 hot dogs and 4 sodas for $9.00. What is the cost of one hot dog and one soda? \n" ); document.write( "
Algebra.Com's Answer #115817 by jojo14344(1513)\"\" \"About 
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Remember: \"Hotdog=H\"--> cost$(?); and \"Soda=S\"--> cost$(?)
\n" ); document.write( "1st group:
\n" ); document.write( "\"10H%2B5S=12.50\" -----------> eqn 1
\n" ); document.write( "2nd group:
\n" ); document.write( "\"7H%2B4S=9.00\" --------------> eqn 2
\n" ); document.write( "In eqn 1 we get,
\n" ); document.write( "\"H=%2812.50-5S%29%2F10\" ----------> eqn 3
\n" ); document.write( "Substitute eqn 3 to eqn 2:
\n" ); document.write( "\"7%28%2812.50-5S%29%2F10%29%2B4S=9\" --->\"%287%2F10%29%2812.50-5S%29%2B4S=9.00\"
\n" ); document.write( "\"8.75-3.5S%2B4S=9\"
\n" ); document.write( "\"0.5S=9-8.75\"
\n" ); document.write( "\"0.5S=0.25\" ----> \"cross%280.5%29S%2Fcross%280.5%29=cross%280.25%290.50%2Fcross%280.50%29\"
\n" ); document.write( "\"S=0.50\" --------------> cost of 1 soda=$0.50/ea
\n" ); document.write( "For hotdog, go eqn 3:
\n" ); document.write( "\"H=%2812.50-%285%2A0.50%29%29%2F10=%2812.50-2.50%29%2F10\"
\n" ); document.write( "\"H=1.00\" -------> cost of 1 hotdog =$1.00/ea
\n" ); document.write( "In doubt? go back eqn 1:
\n" ); document.write( "\"10%281%29%2B5%280.50%29=12.50\"
\n" ); document.write( "\"10%2B2.50=12.50\"
\n" ); document.write( "\"12.50=12.50\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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