document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23124>Question 23124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with this question, please?\r<BR>\n" );
document.write( "\n" );
document.write( "One of the roots of the equation 4x^2-2px+p=0, p is not = 0 is two times the other root. Find the possible value of p. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11578 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11578\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One of the roots of the equation 4x^2-2px+p=0, p is not = 0 is two times the other root. Find the possible value of p.<BR>\n" );
document.write( "LET ONE ROOT BE =K..THEN THE OTHER ROOT IS 2K<BR>\n" );
document.write( "HENCE SUM OF ROOTS =K+2K=3K= -(-2P)/4=P/2....OR.... K=P/6..................I<BR>\n" );
document.write( "PRODUCT OF THE ROOTS =K*2K=2K^2=P/4............................II<BR>\n" );
document.write( "SUBSTITUTING I IN II...WE GET<BR>\n" );
document.write( "2*(P/6)^2=P/4<BR>\n" );
document.write( "2P^2/36=P/4......CROSS MULTIPLYING<BR>\n" );
document.write( "8P^2=36P<BR>\n" );
document.write( "2P^2=9P<BR>\n" );
document.write( "2P^2-9P=0<BR>\n" );
document.write( "P(2P-9)=0<BR>\n" );
document.write( "SINCE P IS NOT EQUAL TO 0 ,WE GET <BR>\n" );
document.write( "2P-9=0<BR>\n" );
document.write( "2P=9<BR>\n" );
document.write( "P=9/2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );