document.write( "Question 156951: A man invested $6000 dollars and if 5% is in simple intrest and the rest is in 7% interest. if the anunal income on the interest is $372 how much money was put in each one? \n" ); document.write( "
Algebra.Com's Answer #115776 by orca(409)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the amount invested at 5%, the the amount invested at 7% is 6000 - x. \n" ); document.write( "The interest earned from the 5% investment is x*5%. \n" ); document.write( "The interest earned from the 7% investment is (6000 - x)*7%. \n" ); document.write( "Their total is 372, we have: \n" ); document.write( "x*5% + (6000 - x)*7% = 372 \n" ); document.write( "Solving the equation for x, we have \n" ); document.write( "5x + 7(6000 - x) = 37200 (multiply both sides by 100) \n" ); document.write( "5x + 42000 - 7x = 37200 \n" ); document.write( "-2x = -4800 \n" ); document.write( "x = 2400 \n" ); document.write( "So \n" ); document.write( "the amount invested at 5% is $2400. \n" ); document.write( "the amount invested at 7% is 6000 - x = 6000 - 2400 = $3600.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |