document.write( "Question 157012: hey i will greatly appreciate it if you could help me with this probability question:\r
\n" ); document.write( "\n" ); document.write( "Two cards are drawn from a deck of 52 playing cards. Find the probability of each of the following events occuring:\r
\n" ); document.write( "\n" ); document.write( "a) Both cards are clubs
\n" ); document.write( "b) Both cards are red
\n" ); document.write( "c) Both cards are queens
\n" ); document.write( "d) Both cards are red queens
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Algebra.Com's Answer #115771 by gonzo(654)\"\" \"About 
You can put this solution on YOUR website!
52 cards in the deck (not counting the joker).
\n" ); document.write( "4 suits with 13 cards each (ace through 10 + jack queen king)
\n" ); document.write( "26 red
\n" ); document.write( "4 queens
\n" ); document.write( "2 red queens
\n" ); document.write( "probability of drawing 2 clubs is (13/52) * (12/51)
\n" ); document.write( "probability of drawing 2 red cards is (26/52) * (25/51)
\n" ); document.write( "probability of drawing 2 queens is (4/52) * (3/51)
\n" ); document.write( "probability of drawing 2 red queens is (2/52) * (1/51).
\n" ); document.write( "here's how it works.
\n" ); document.write( "the probability of any event happening is the number of ways it can happen divided by the total number of ways anything can happen.
\n" ); document.write( "the probability of any 2 events happening is the probability of the first event happening times the probability of the second event happening.
\n" ); document.write( "with the cards, there are 13 clubs in the deck.
\n" ); document.write( "the probability of getting a club is 13 / 52 because there are 52 total cards in the deck.
\n" ); document.write( "once the club has been taken, there are 12 clubs left in the deck and 51 cards total, so the probability of a club being taken again is 12 / 51.
\n" ); document.write( "the probability of both events happening is the probability of the first event times the probability of the second event so the answer is (13/52) * (12/51).
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