document.write( "Question 156941: Find the vertex, line of symmetry, the maximum or minimum value of the quadratic equation, and graph the function. f(x)= -2x^2+2x+6 \n" ); document.write( "
Algebra.Com's Answer #115741 by Alan3354(69443)\"\" \"About 
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Find the vertex, line of symmetry, the maximum or minimum value of the quadratic equation, and graph the function. f(x)= -2x^2+2x+6
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\n" ); document.write( "set f(x) = 0 to find where it crosses the x-axis.
\n" ); document.write( "-2x^2+2x+6=0
\n" ); document.write( "x^2 - x - 3 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-1x%2B-3+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1%29%5E2-4%2A1%2A-3=13\".
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\n" ); document.write( " Discriminant d=13 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1%2B-sqrt%28+13+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-1%29%2Bsqrt%28+13+%29%29%2F2%5C1+=+2.30277563773199\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-1%29-sqrt%28+13+%29%29%2F2%5C1+=+-1.30277563773199\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-1x%2B-3\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-1x%2B-3+=+%28x-2.30277563773199%29%2A%28x--1.30277563773199%29\"
\n" ); document.write( " Again, the answer is: 2.30277563773199, -1.30277563773199.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1%2Ax%2B-3+%29\"

\n" ); document.write( "\n" ); document.write( "The vertex is at the minimum: set the 1st derivative to 0
\n" ); document.write( "2x-1=0
\n" ); document.write( "x = 1/2
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\n" ); document.write( "sub for x in the eqn
\n" ); document.write( "y = (1/4) - 1/2 - 3
\n" ); document.write( "y = -3 1/4 = -13/4
\n" ); document.write( "So the vertex is at (1/2,-13/4)\r
\n" ); document.write( "\n" ); document.write( "Since there's no xy term, the axis of symmetry is parallel to the y-axis. It goes thru the vertex, so it's:
\n" ); document.write( "x = 1/2\r
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