document.write( "Question 156941: Find the vertex, line of symmetry, the maximum or minimum value of the quadratic equation, and graph the function. f(x)= -2x^2+2x+6 \n" ); document.write( "
Algebra.Com's Answer #115741 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the vertex, line of symmetry, the maximum or minimum value of the quadratic equation, and graph the function. f(x)= -2x^2+2x+6 \n" ); document.write( "----------- \n" ); document.write( "set f(x) = 0 to find where it crosses the x-axis. \n" ); document.write( "-2x^2+2x+6=0 \n" ); document.write( "x^2 - x - 3 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The vertex is at the minimum: set the 1st derivative to 0 \n" ); document.write( "2x-1=0 \n" ); document.write( "x = 1/2 \n" ); document.write( "--------- \n" ); document.write( "sub for x in the eqn \n" ); document.write( "y = (1/4) - 1/2 - 3 \n" ); document.write( "y = -3 1/4 = -13/4 \n" ); document.write( "So the vertex is at (1/2,-13/4)\r \n" ); document.write( "\n" ); document.write( "Since there's no xy term, the axis of symmetry is parallel to the y-axis. It goes thru the vertex, so it's: \n" ); document.write( "x = 1/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |