document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156936>Question 156936</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534434215/algebrahomeworkh>PRECALCULUS Mathmatics for Calculus 4th</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I can't figure out how to even start this:<BR>\n" );
document.write( "The hypotenuse of a right triangle has length 20 cm. The sum of the lengths of the other two sides is 28 cm. Find the lengths of the other two sides of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115705 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one of the sides be \"x\"; Let the other side be \"28-x'\r<BR>\n" );
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document.write( "Use Pythagoras to find \"s\" and 28-x:\r<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "x^2 + (28-x)^2 = 20^2<BR>\n" );
document.write( "x^2 + 784 - 56x + x^2 = 400<BR>\n" );
document.write( "2x^2 -56x + 384 = 0<BR>\n" );
document.write( "x^2 - 28x + 192 = 0<BR>\n" );
document.write( "(x-12)(x-16) = 0<BR>\n" );
document.write( "x = 12 or x = 16<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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