document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156924>Question 156924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write a linear equation in standard form, given the following information...\r<BR>\n" );
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document.write( "A line through -3,2  and parallel to a line with a slope of -4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115701 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe this meets your requirements.<BR>\n" );
document.write( "check it out and let me know what you think.<BR>\n" );
document.write( "i used the slope intercept formula to get the equation.<BR>\n" );
document.write( "the formula is:  y = mx + b where m is the slope and b is the y-intercept.<BR>\n" );
document.write( "i started with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-4x ALIGN=MIDDLE  ALT=\"y+=+-4x\"   DISABLED_style= \"max-width:90%; height:auto;\" > since -4 is the slope of the line you wanted this line to be parallel to.<BR>\n" );
document.write( "getting the y intercept was a little tricky but here's how i did it.<BR>\n" );
document.write( "i plotted for x points from -5 to + 5.<BR>\n" );
document.write( "i then started with x = -3 to fix the line to pass through where you wanted it to.  i set the y value at 2 at that point (line goes through (-3,2).<BR>\n" );
document.write( "with a slope of -4 there is a drop of 4 units in the y value for every increase of 1 unit in the x value.  conversely there is an increase of 4 units in the y value for every decrease of 1 unit in the x value.<BR>\n" );
document.write( "the plot poiints look like the following:<BR>\n" );
document.write( "start of plot points........<BR>\n" );
document.write( "x,y<BR>\n" );
document.write( "-5,10<BR>\n" );
document.write( "-4,6<BR>\n" );
document.write( "-3,2<BR>\n" );
document.write( "-2,-2<BR>\n" );
document.write( "-1,-6<BR>\n" );
document.write( "0,-10<BR>\n" );
document.write( "1,-14<BR>\n" );
document.write( "2,-18<BR>\n" );
document.write( "3,-22<BR>\n" );
document.write( "4,-26<BR>\n" );
document.write( "5,-20<BR>\n" );
document.write( "end of plot points.............<BR>\n" );
document.write( "looking at this table i saw that the y-intercept (y value when x is 0) is -10.<BR>\n" );
document.write( "the equation then becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-4x-10 ALIGN=MIDDLE  ALT=\"y=-4x-10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "the graph looks like the following:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C1200%2C-5%2C5%2C-20%2C10%2C-4x-10%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C1200%2C-5%2C5%2C-20%2C10%2C-4x-10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "an algebraic way to find the b value in the equation would be as follows:<BR>\n" );
document.write( "starting with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-4x ALIGN=MIDDLE  ALT=\"y+=+-4x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, i would solve the equation for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3 ALIGN=MIDDLE  ALT=\"x+=+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-4+%2A+-3 ALIGN=MIDDLE  ALT=\"y+=+-4+%2A+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+12 ALIGN=MIDDLE  ALT=\"y+=+12\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "the answer i want is 2 so i would need to subtract 10 from it.<BR>\n" );
document.write( "that becomes my b value, so the equation then becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-4x-10 ALIGN=MIDDLE  ALT=\"y+=+-4x-10\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is the same result without looking at plot points.<BR>\n" );
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