document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23110>Question 23110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.The length of a rectangular playing field is 5 ft less than twice its width.<BR>\n" );
document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field.\r<BR>\n" );
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document.write( "2.A bicyclist rode into the country for 5 h. In returning, her<BR>\n" );
document.write( "speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?\r<BR>\n" );
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document.write( "3. A bus leaves a station at 1 P.M., traveling west at an average<BR>\n" );
document.write( "rate of 44 mi/h. One hour later a second bus leaves the same station, traveling<BR>\n" );
document.write( "east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?\r<BR>\n" );
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document.write( "4. Mika leaves Boston for Baltimore at 10:00 A.M., traveling at<BR>\n" );
document.write( "45 mi/h. One hour later, Hiroko leaves Baltimore for Boston on the same route, traveling<BR>\n" );
document.write( "at 50 mi/h. If the two cities are 425 mi apart, when will Mika and Hiroko meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11570 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 2(2x-5+x)=230<BR>\n" );
document.write( "6x-10=230<BR>\n" );
document.write( "6x=240<BR>\n" );
document.write( "x=40<BR>\n" );
document.write( "2(40)-5=75<BR>\n" );
document.write( "Hence, the width is 40cm and the length is 75cm.\r<BR>\n" );
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document.write( "2.5x=4(x+5)<BR>\n" );
document.write( "5x=4x+20<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( "20+5 = 25<BR>\n" );
document.write( "Hence her two speeds were 20miles per hours and 25 miles per hour.\r<BR>\n" );
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document.write( "3.44(t+1)+48t=274<BR>\n" );
document.write( "44t+44+48t=274<BR>\n" );
document.write( "92t=230<BR>\n" );
document.write( "t=2.5<BR>\n" );
document.write( "Hence, at 2.5h they will be 274 miles apart.\r<BR>\n" );
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document.write( "4.45(t+1)+50t=425<BR>\n" );
document.write( "45t+45+50t=425 <BR>\n" );
document.write( "95t=380<BR>\n" );
document.write( "t=4<BR>\n" );
document.write( "10:00+4 = 2:00p.m.<BR>\n" );
document.write( "Hence after 4h or at 2:00 p.m. ; they will meet. </SPAN>\n" );
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