document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156837>Question 156837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trains a and b sre traveling in the same direction on parallel tracks.  train a is traveling at 40 mile per hour and train b is traveling at 60 miles per hour.  train a passes a station at 5:25pm.  if train b pass the same station at 5:37pm what time will train b catch up to train a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115681 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40t=60(t-.2)<BR>\n" );
document.write( "40t=60t-12<BR>\n" );
document.write( "40t-60t=-12<BR>\n" );
document.write( "-20t=-12<BR>\n" );
document.write( "t=-12/-20<BR>\n" );
document.write( "t=.6 hours or 36 minutes they will meet.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "40*.6=60(.6-.2)<BR>\n" );
document.write( "24=60*.4<BR>\n" );
document.write( "24=24  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );