document.write( "Question 156863: At 11:00a.m. Kate left the Clinton toll booth traveling west at 80 km/h. At 12:00p.m. Juan left the toll booth traveling west at 72 km/h. At what time will the two cars be 98 km apart?\r
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document.write( "This is what I have so far...Kate: 80(x+1)
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document.write( " Juan: 72x
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document.write( " 80(x+1)+72x=98
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document.write( " 152x=18
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document.write( " x=.118
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document.write( "Not sure what to do after this..thanks. \n" );
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Algebra.Com's Answer #115678 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 80(x+1)+72x=98 \n" ); document.write( "------------------------------------------ \n" ); document.write( "Equation should be 80(t+1)-72t=98 \n" ); document.write( "80t+80-72t=98 \n" ); document.write( "8t=98-80 \n" ); document.write( "8t=18 \n" ); document.write( "t=18/8 \n" ); document.write( "t=2.25 hours they'll be 98 miles apart. \n" ); document.write( "Proof: \n" ); document.write( "80(2.25+1)-72*2.25=98 \n" ); document.write( "80*3.25-162=98 \n" ); document.write( "260-162=98 \n" ); document.write( "98=98 \n" ); document.write( "----------------------------------------- \n" ); document.write( "152x=18 \n" ); document.write( "x=.118 \n" ); document.write( " \n" ); document.write( " |