document.write( "Question 156836: I need to resolve x, AB, BC and AC, where A, B and C are points on a line. A is leftmost, C is rightmost, and B is somewhere in between.\r
\n" ); document.write( "\n" ); document.write( "AB = 2x+1
\n" ); document.write( "BC = x-2
\n" ); document.write( "AC = sqrt (x^2 + 25x + 5)\r
\n" ); document.write( "\n" ); document.write( "Was able to write, 2x+1+x-2 = sqrt (x^2+25x+5), which reduces to 3x-1 = sqrt (x^2 + 25x + 5).\r
\n" ); document.write( "\n" ); document.write( "I don't know how to eliminate the square root, especially when there is an exponential along with it.\r
\n" ); document.write( "\n" ); document.write( "Please help.\r
\n" ); document.write( "\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #115629 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll start where you left off\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x-1+=+sqrt+%28x%5E2+%2B+25x+%2B+5%29\" Start with the given equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%283x-1%29%5E2+=+x%5E2+%2B+25x+%2B+5\" Square both sides. This will eliminate the square root.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"9x%5E2-6x%2B1+=+x%5E2+%2B+25x+%2B+5\" FOIL the left side\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"9x%5E2-6x%2B1-x%5E2-25x-5=0\" Subtract \"x%5E2\" from both sides. Subtract \"25x\" from both sides. Subtract \"5\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"8x%5E2-31x-4=0\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=8\", \"b=-31\", and \"c=-4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-31%29+%2B-+sqrt%28+%28-31%29%5E2-4%288%29%28-4%29+%29%29%2F%282%288%29%29\" Plug in \"a=8\", \"b=-31\", and \"c=-4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+sqrt%28+%28-31%29%5E2-4%288%29%28-4%29+%29%29%2F%282%288%29%29\" Negate \"-31\" to get \"31\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+sqrt%28+961-4%288%29%28-4%29+%29%29%2F%282%288%29%29\" Square \"-31\" to get \"961\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+sqrt%28+961--128+%29%29%2F%282%288%29%29\" Multiply \"4%288%29%28-4%29\" to get \"-128\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+sqrt%28+961%2B128+%29%29%2F%282%288%29%29\" Rewrite \"sqrt%28961--128%29\" as \"sqrt%28961%2B128%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+sqrt%28+1089+%29%29%2F%282%288%29%29\" Add \"961\" to \"128\" to get \"1089\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+sqrt%28+1089+%29%29%2F%2816%29\" Multiply \"2\" and \"8\" to get \"16\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B-+33%29%2F%2816%29\" Take the square root of \"1089\" to get \"33\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2831+%2B+33%29%2F%2816%29\" or \"x+=+%2831+-+33%29%2F%2816%29\" Break up the expression. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2864%29%2F%2816%29\" or \"x+=++%28-2%29%2F%2816%29\" Combine like terms. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+4\" or \"x+=+-1%2F8\" Simplify. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the possible answers are \"x+=+4\" or \"x+=+-1%2F8\" \r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "However, if you plug in \"x+=+-1%2F8\" back into the original equation, you'll find that the equation won't be true. Also, since distance is ALWAYS positive, this means that \"x+=+-1%2F8\" will not work (since if you plug it into any expression the result is negative)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the only answer is \"x+=+4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now plug in \"x=4\" into AB,BC, and AC:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "AB = \"2x%2B1=2%284%29%2B1=8%2B1=9\"
\n" ); document.write( "BC = \"x-2=%284%29-2=2\"
\n" ); document.write( "AC = \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the three lengths are \"AB=9\", \"BC=2\", and \"AC=11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remember, the segment addition postulate is AB+BC=AC (ie the lengths of the pieces of AC should add to the length of AC)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "AB+BC=AC ... Start with the given equation\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "9+2=11 ...Plug in AB=9, BC=2, and AC=11\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "11=11 ... Add. Since this equation is true, this verifies the answer.
\n" ); document.write( "
\n" );