document.write( "Question 156822This question is from textbook Glencoe Algebra 2
\n" ); document.write( ": $\"X+plus+8%2F4-1%3Ex%2F3\"$ . I tried to answer it by multiplying by the recipricals of the equation. When I did that, I got $\"x%2B8-1%3Ex\"$ . Then I subtracted the 1 and got $\"x%2B7%3Ex\"$ . After that,I subtracted 7 from both sides. When I did, I got $\"x%3E-7\"$ as my answer. I don't know if that is right. \n" ); document.write( "

Algebra.Com's Answer #115623 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"%28x%2B8%29%2F4+-1+%3E+x%2F3\"$ Multiply both sides by 3.
\n" ); document.write( " $\"%283x%2B24%29%2F4+-+3+%3E+x\"$ Mu;tiply both sides by 4.
\n" ); document.write( " $\"3x%2B24-12+%3E+4x\"$ Simplify.
\n" ); document.write( " $\"3x%2B12+%3E+4x\"$ Subtract 3x from both sides.
\n" ); document.write( " $\"12+%3E+x\"$ or $\"x+%3C+12\"$ \n" ); document.write( "

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