document.write( "Question 156813: A hardware store sells large nails for $5.00 per killogram and small nails for $2.00 per killogram. The owner wants to mix the nails tog et 20 kg. of a mixture that would sell for $3.50 per killogram. How many killograms of each size does the owner need. \n" ); document.write( "

Algebra.Com's Answer #115621 by nerdybill(7384) $\"\"$ $\"About$

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A hardware store sells large nails for $5.00 per killogram and small nails for $2.00 per killogram. The owner wants to mix the nails tog et 20 kg. of a mixture that would sell for $3.50 per killogram. How many killograms of each size does the owner need.
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\n" ); document.write( "Let L = weight of large nails
\n" ); document.write( "then, since total weight is 20 kg:
\n" ); document.write( "20-L = weight of small nails
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\n" ); document.write( "\"cost of large nails\" + \"cost of small nails\" = \"cost of mixture\"
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\n" ); document.write( "5L + 2(20-L) = 3.50(20)
\n" ); document.write( "5L + 40 - 2L = 70
\n" ); document.write( "3L = 30
\n" ); document.write( "L = 10 kilogram (weight of large nails)
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\n" ); document.write( "For small nails:
\n" ); document.write( "20 - L = 20 - 10 = 10 kilogram (weight of small nails)
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