document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156815>Question 156815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of antifreeze must be added to 10 kg. of 20% antifreeze solution to produce a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115620 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     How many kilograms of antifreeze must be added to 10 kg. of 20% antifreeze solution to produce a 50% solution?<BR>\n" );
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document.write( "Let x = amount of 100% antifreeze added<BR>\n" );
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document.write( "\"amt of antifreeze added\" + \"amt of antifreeze in original solution\" = \"50% of volume of new mixture\"<BR>\n" );
document.write( "mathematically, it would be:<BR>\n" );
document.write( "x + .20(10) = .50(x+10)<BR>\n" );
document.write( "x + 2 = .5x + 5<BR>\n" );
document.write( ".5x = 3<BR>\n" );
document.write( "x = 6 kg<BR>\n" );
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