document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156804>Question 156804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two acid solutions.One contains 15 percent acid and the other contains 6 percent acid. How many cubic meters of each solution should be used to obtain 400 cm^3 of a solution that is 9 percent acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115618 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=cm^3 of 15%, so 400-x=cm^3 of 6%\r<BR>\n" );
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document.write( "(15%)(x)+(6%)(400-x)=(9%)(400) __ multiply by 100 to clear percentages\r<BR>\n" );
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document.write( "15x+2400-6x=3600 __ subtracting 2400 __ 9x=1200 dividing by 9 __ x=400/3\r<BR>\n" );
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document.write( "substituting __ 400-(400/3)=800/3 </SPAN>\n" );
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