document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156799>Question 156799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x^3-24\r<BR>\n" );
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document.write( "Since 24 is not a perfect cube I think I factor out the 3 as follows:<BR>\n" );
document.write( "3(x^3-8)<BR>\n" );
document.write( "Am I on the right track? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115601 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes.<BR>\n" );
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document.write( "After pulling out the 3, the remainder is a \"difference of cubes\" -- now, you can apply \"special factoring\".<BR>\n" );
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document.write( "See:<BR>\n" );
document.write( "http://www.purplemath.com/modules/specfact2.htm<BR>\n" );
document.write( "for detailed information<BR>\n" );
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document.write( "3(x^3-8)<BR>\n" );
document.write( "3(x-2)(x^2 + 2x + 2^2)<BR>\n" );
document.write( "3(x-2)(x^2 + 2x + 4)<BR>\n" );
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