document.write( "Question 156728: (x - 3)2 = 49 \n" ); document.write( "
Algebra.Com's Answer #115567 by jim_thompson5910(35256)\"\" \"About 
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Is the equation \"%28x+-+3%29%5E2+=+49\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2=49\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=0%2B-sqrt%2849%29\" Take the square root of both sides. Note: don't forget the \"plus/minus\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=sqrt%2849%29\" or \"x-3=-sqrt%2849%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=7\" or \"x-3=-7\" Take the square root of \"49\" to get \"7\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2B7\" or \"x=3-7\" Add \"3\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=10\" or \"x=-4\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=10\" or \"x=-4\".
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