document.write( "Question 22425: graph y-5=-2(x+3) \n" ); document.write( "
Algebra.Com's Answer #11556 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! If you have been working with the point-slope formula, you may recognize tht this graph y-5=-2(x+3) passes through the point (-3, 5), and the slope is m=-2. If you recognize this fact, then graph the point (-3, 5). From that point measure a distance that is DOWN 2, and one unit to the RIGHT, and put a second point. Draw the line, and you have it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you did NOT understand the previous paragraph (my own students would have NO CLUE as what that was all about!!), there is actually an EASIER way that always works. Solve for y, and write the equation is slope-intercept form:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y-5=-2(x+3) \n" ); document.write( "y-5 = -2x -6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add +5 to each side: \n" ); document.write( "y-5+5 = -2x -6 +5 \n" ); document.write( "y= -2x -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From looking at this, you can easily see that the slope is m=-2 and the y intercept is -1. So graph the y-intercept by going DOWN one unit on the y-axis. Put a point there. Then from that point, measure DOWN two more units, then move 1 unit to the right, and put a second point. Connect those two points, and you have your line that should look like this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |