document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156716>Question 156716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the length of one side of a triangle. If a triangle that has the second side 10 feet shorter than the first side.  The third side is 50 feet longer than the first side.  The perimeter is 684 feet.  How long is the first side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115548 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115548\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S=F-10<BR>\n" );
document.write( "T=F+50<BR>\n" );
document.write( "F=FIRST SIDE<BR>\n" );
document.write( "F+(F-10)+(F+50)=684<BR>\n" );
document.write( "3F-10+50=684<BR>\n" );
document.write( "3F=684-50+10<BR>\n" );
document.write( "3F=644<BR>\n" );
document.write( "F=644/3<BR>\n" );
document.write( "F=214 2/3 IS THE LENGTH OF THE FIRST SIDE.<BR>\n" );
document.write( "214 2/3-10=204 2/3 FOR THE SECOND SIDE.<BR>\n" );
document.write( "214 2/3+50=264 2/3 FOR THE THIRD SIDE.<BR>\n" );
document.write( "pROOF:<BR>\n" );
document.write( "214 2/3+204 2/3+264 2/3=684<BR>\n" );
document.write( "682+6/3=684<BR>\n" );
document.write( "684=684\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );