document.write( "Question 156693This question is from textbook Algebra 1 An Incremental Development
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\n" ); document.write( "4x + 2 = x^2
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Algebra.Com's Answer #115516 by jim_thompson5910(35256)\"\" \"About 
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\"4x+%2B+2+=+x%5E2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"4x+%2B+2+-+x%5E2=0\" Subtract \"x%5E2\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-+x%5E2%2B4x+%2B+2+=0\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "So let's complete the square for \"-x%5E2%2B4x%2B2\" \r
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\n" ); document.write( "\n" ); document.write( "\"-x%5E2%2B4x%2B2\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x%5E2-4x-2%29\" Factor out the \"x%5E2\" coefficient \"-1\". This step is very important: the \"x%5E2\" coefficient MUST be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"-4\" to get \"-2\". In other words, \"%281%2F2%29%28-4%29=-2\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"-2\" to get \"4\". In other words, \"%28-2%29%5E2=%28-2%29%28-2%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x%5E2-4x%2Bhighlight%284-4%29-2%29\" Now add and subtract \"4\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"4-4=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28%28x%5E2-4x%2B4%29-4-2%29\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28%28x-2%29%5E2-4-2%29\" Factor \"x%5E2-4x%2B4\" to get \"%28x-2%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28%28x-2%29%5E2-6%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x-2%29%5E2-1%28-6%29\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x-2%29%5E2%2B6\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"-x%5E2%2B4x%2B2\" transforms to \"-1%28x-2%29%5E2%2B6\". So \"-x%5E2%2B4x%2B2=-1%28x-2%29%5E2%2B6\".\r
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\n" ); document.write( "\n" ); document.write( "So \"-x%5E2%2B4x%2B2=0\" is equivalent to \"-1%28x-2%29%5E2%2B6=0\".\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x-2%29%5E2%2B6=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x-2%29%5E2=0-6\"Subtract \"6\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x-2%29%5E2=-6\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2=%28-6%29%2F%28-1%29\" Divide both sides by \"-1\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2=6\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0%2B-sqrt%286%29\" Take the square root of both sides. Note: remember the \"plus/minus\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=sqrt%286%29\" or \"x-2=-sqrt%286%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2Bsqrt%286%29\" or \"x=2-sqrt%286%29\" Add \"2\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=2%2Bsqrt%286%29\" or \"x=2-sqrt%286%29\".
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