document.write( "Question 156686: The problem is: Evaluate and find the domain. f(x)=1/x^2-9 for x=4,a-5\r
\n" ); document.write( "\n" ); document.write( "I am able to evaluate and came up with f(4)=1/7 and f(4)=1/a^2-10a+16. What I don't understand is how to find the domain. I know my book says the answer is: x is not equal to 3, and x is not equal to -3. I just don't know how the domain came to be this, I don't understand how to find the domain. Please help.\r
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Algebra.Com's Answer #115506 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Well notice how if \"x=3\", then \"f%283%29=1%2F%28%283%29%5E2-9%29=1%2F%289-9%29=1%2F0\" which is NOT defined. Also, if \"x=-3\", then \"f%283%29=1%2F%28%28-3%29%5E2-9%29=1%2F%289-9%29=1%2F0\" which is also NOT defined. So that's why there are domain restrictions of \"x%3C%3E-3\" and \"x%3C%3E3\" \n" ); document.write( "
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