document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156684>Question 156684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thanks for any insight you may be able to give me...\r<BR>\n" );
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document.write( "This question is from a quiz my instructor gave to us. He says the questions come from a textbook.\r<BR>\n" );
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document.write( "How many liters of a 70% acid solution are needed to be mixed with 18 liters of a 10% acid solution to get a mixture which is 25% alcohol?\r<BR>\n" );
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document.write( "If the solution contains acid/alcohol you would need 75% acid to leave you with 25% alcohol. How is it even possible to get 75% when both solutions you are using are diluted below 75%. As far as I have tried I see no possible solution to this problem, if he meant 25% acid then it would be easy to answer.\r<BR>\n" );
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document.write( "Let me know what you think, thanks for your time,\r<BR>\n" );
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document.write( "Bill W </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115502 by </B><A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><B>mangopeeler07(462)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 70% acid solution are needed to be mixed with 18 liters of a 10% acid solution to get a mixture which is 25% alcohol? \r<BR>\n" );
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document.write( "Alcohol? Yes, he probably meant to say \"acid\".  Let's work it out for acid.\r<BR>\n" );
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document.write( "How many liters of a 70% acid solution are needed to be mixed with 18 liters of a 10% acid solution to get a mixture which is 25% ACID? \r<BR>\n" );
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document.write( "(amount of liters)<BR>\n" );
document.write( "coefficient=percent\r<BR>\n" );
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document.write( "70(x)+10(18)=25(x+18)\r<BR>\n" );
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document.write( "Distribute everything.<BR>\n" );
document.write( "70x+180=25x+450\r<BR>\n" );
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document.write( "Subtract 25x from both sides<BR>\n" );
document.write( "45x+180=450\r<BR>\n" );
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document.write( "Subtract 180 from both sides<BR>\n" );
document.write( "45x=270\r<BR>\n" );
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document.write( "Divide both sides by 45<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "Answer: 6 liters<BR>\n" );
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document.write( "Now let's assume he actually meant alcohol.  25% alcohol means 75% acid.  So: \r<BR>\n" );
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document.write( "(amount of liters)<BR>\n" );
document.write( "coefficient=percent\r<BR>\n" );
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document.write( "70(x)+10(18)=75(x+18)\r<BR>\n" );
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document.write( "Do you follow?<BR>\n" );
document.write( "25 is changed to 75 because it is 75% acid now.\r<BR>\n" );
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document.write( "Distribute, like before<BR>\n" );
document.write( "70x+180=75x+1350\r<BR>\n" );
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document.write( "Subtract 75x from both sides<BR>\n" );
document.write( "-5x+180=1350\r<BR>\n" );
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document.write( "Subtract 180 from both sides<BR>\n" );
document.write( "-5x=1170\r<BR>\n" );
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document.write( "Divide by -5<BR>\n" );
document.write( "x=-234\r<BR>\n" );
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document.write( "Negative means you would have to subtract, and logically speaking, you wouldn't <i>take away</i> acid to <i>increase</i> the percentage of acid.  Therefore, the logical answer is:\r<BR>\n" );
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document.write( "6 liters<BR>\n" );
document.write( "-------------------------------------------------------\r<BR>\n" );
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document.write( "I hope this helped!<BR>\n" );
document.write( "-Alani<BR>\n" );
document.write( " </SPAN>\n" );
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