document.write( "Question 156680This question is from textbook Intermediate Algebra
\n" );
document.write( ": \"Use the Addition Property and/or Multiplication Properties to find a and b. If -3 < x < 4, then a < x + 4 < b.\"\r
\n" );
document.write( "\n" );
document.write( "I have tried substituting the \"if\" equation in for x in the \"then\" equation, but just can't seem to get anywhere. The back of the book indicates that the correct answer is a=1 and b=8. I can't figure out how to move from an inequality to an answer with an equality. \n" );
document.write( "
Algebra.Com's Answer #115497 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! -3 < x < 4 \n" ); document.write( "a < x + 4 < b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a=? \n" ); document.write( "b=!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simply take -3 < x < 4 and add 4 to all three \"sides\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3+4 < x+4 < 4+4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify \n" ); document.write( "1 < x+4 < 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a < x+4 < b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which numbers take the place of a and b? 1 and 8. Therefore: \n" ); document.write( "a=1 \n" ); document.write( "b=8 \n" ); document.write( " \n" ); document.write( " |