document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156258>Question 156258</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618250204/algebrahomeworkh>Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> xy+3x=25       x=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115445 by </B><A HREF=/tutors/aboutme.mpl?userid=mizjoice><B>mizjoice(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mizjoice><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this problem, you start by working with the variables you do know. xy +3x =25.  x=5. xy +3(5)=25, xy + 15=25. If 15 + xy=25, that means that 25-15=xy.  To follow the steps of the problem, from the beginning:<BR>\n" );
document.write( "xy +3x=25, x=5.<BR>\n" );
document.write( "5y +3(5)= 25<BR>\n" );
document.write( "5y +15=25<BR>\n" );
document.write( "5y +15 -15= 25-15<BR>\n" );
document.write( "5y=10<BR>\n" );
document.write( "5y/5 = 10/5<BR>\n" );
document.write( "y=2\r<BR>\n" );
document.write( "\n" );
document.write( "Check by substituting 2 for y:\r<BR>\n" );
document.write( "\n" );
document.write( "5(2)+ 3(5)= 25<BR>\n" );
document.write( "10+15=25<BR>\n" );
document.write( "25=25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );