document.write( "Question 156636: graph the quadritic equation\r
\n" ); document.write( "\n" ); document.write( "y= x^2 +2x
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Algebra.Com's Answer #115436 by Alan3354(69443)\"\" \"About 
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y= x^2 +2x
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B2x%2B0+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A1%2A0=4\".
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\n" ); document.write( " Discriminant d=4 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+4+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+4+%29%29%2F2%5C1+=+0\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+4+%29%29%2F2%5C1+=+-2\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B2x%2B0\" can be factored:
\n" ); document.write( " \"1x%5E2%2B2x%2B0+=+%28x-0%29%2A%28x--2%29\"
\n" ); document.write( " Again, the answer is: 0, -2.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B0+%29\"

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\n" ); document.write( "The y-intercept is at x=0.
\n" ); document.write( "At x=0, y=0 so the y-intercept is (0,0)
\n" ); document.write( "The vertex is at the minimum (in this example).
\n" ); document.write( "The 1st derivative is 2x+2
\n" ); document.write( "2x+2=0
\n" ); document.write( "x = -1
\n" ); document.write( "at x = -1, y = -1, so the vertex is (-1,-1)
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