document.write( "Question 23109: the height of a triangle is three feet longer than the base. the area of the triangle is 35 square feet. find the height and base of the triangle. \n" ); document.write( "
Algebra.Com's Answer #11543 by rapaljer(4671)\"\" \"About 
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Let x = base
\n" ); document.write( "x+3 = height\r
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\n" ); document.write( "\n" ); document.write( "Area = 1/2*b*h= 35
\n" ); document.write( "\"%281%2F2%29%2Ax%2A%28x%2B3%29+=+35\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 2:
\n" ); document.write( "\"x%28x%2B3%29=+70\"
\n" ); document.write( "\"x%5E2+%2B3x+-+70=0\"
\n" ); document.write( "\"%28x%2B10%29%28x-7%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "First solution:
\n" ); document.write( "x=-10 reject this solution!\r
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\n" ); document.write( "\n" ); document.write( "Second solution:
\n" ); document.write( "x= 7 feet = base
\n" ); document.write( "x+3= 10 feet = height\r
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\n" ); document.write( "\n" ); document.write( "Check: Area = 1/2*b*h = 1/2*7*10= 35 square feet\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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