document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156612>Question 156612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wire 350 mm long is cut in two pieces. The first piece is shaped into a circle, and the second piece is shaped into a square. Both shapes have the same area. What is the length of each wire?<BR>\n" );
document.write( "I have no idea where to even start on this problem, so please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115420 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i think i got it.<BR>\n" );
document.write( "area of a circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+pi+%2A+r%5E2 ALIGN=MIDDLE  ALT=\"+pi+%2A+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "area of square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2 ALIGN=MIDDLE  ALT=\"s%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+=+pi+%2A+r%5E2 ALIGN=MIDDLE  ALT=\"s%5E2+=+pi+%2A+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is a requirement.<BR>\n" );
document.write( "if <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+=+pi+%2A+r%5E2 ALIGN=MIDDLE  ALT=\"s%5E2+=+pi+%2A+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+sqrt+%28pi+%2A+r%5E2%29 ALIGN=MIDDLE  ALT=\"s+=+sqrt+%28pi+%2A+r%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+%2A+sqrt+%28pi%29 ALIGN=MIDDLE  ALT=\"r+%2A+sqrt+%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "circumference of a circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2Ar ALIGN=MIDDLE  ALT=\"2%2Api%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "perimeter of a square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2As ALIGN=MIDDLE  ALT=\"4%2As\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "circumference of the circle plus the perimeter of the square must equal 350mm, so the second formula required is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2Api%2Ar%29+%2B+%284%2As%29+=+350 ALIGN=MIDDLE  ALT=\"%282%2Api%2Ar%29+%2B+%284%2As%29+=+350\"   DISABLED_style= \"max-width:90%; height:auto;\" > mm. <BR>\n" );
document.write( "from the first formula we determined that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+r+%2A+sqrt+%28pi%29 ALIGN=MIDDLE  ALT=\"s+=+r+%2A+sqrt+%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "substituting for s in the second equation to eliminate one unknown we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%282%2Api%2Ar%29+%2B+%284+%2A+r+%2A+sqrt+%28pi%29%29+=+350 ALIGN=MIDDLE  ALT=\"+%282%2Api%2Ar%29+%2B+%284+%2A+r+%2A+sqrt+%28pi%29%29+=+350\"   DISABLED_style= \"max-width:90%; height:auto;\" > mm.<BR>\n" );
document.write( "factoring out the r we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+%2A+%28%282+%2A+pi%29+%2B+%284+%2A+sqrt+%28pi%29+%29%29+=+350+ ALIGN=MIDDLE  ALT=\"r+%2A+%28%282+%2A+pi%29+%2B+%284+%2A+sqrt+%28pi%29+%29%29+=+350+\"   DISABLED_style= \"max-width:90%; height:auto;\" > mm.<BR>\n" );
document.write( "solving for r, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+r+=+350+%2F+%28%282+%2A+pi%29+%2B+%284+%2A+sqrt+%28pi%29+%29%29+ ALIGN=MIDDLE  ALT=\"+r+=+350+%2F+%28%282+%2A+pi%29+%2B+%284+%2A+sqrt+%28pi%29+%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "after doing the calculations, r becomes 26.1721365.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2Ar ALIGN=MIDDLE  ALT=\"2%2Api%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" > becomes 164.4443835.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2As ALIGN=MIDDLE  ALT=\"4%2As\"   DISABLED_style= \"max-width:90%; height:auto;\" > becomes 350 - 164.4443835 becomes 185.5556165.<BR>\n" );
document.write( "s becomes 46.38890413.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi+%2A+r%5E2 ALIGN=MIDDLE  ALT=\"pi+%2A+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > becomes 2151.930426<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2 ALIGN=MIDDLE  ALT=\"s%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > becomes 2151.930426<BR>\n" );
document.write( "area of square equals area of circle.<BR>\n" );
document.write( "perimeter of circle plus perimeter of square = 350 mm.<BR>\n" );
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