document.write( "Question 156414: Function Table
\n" ); document.write( "In Out
\n" ); document.write( "2 .6
\n" ); document.write( "4 2.2
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\n" ); document.write( "\n" ); document.write( "What is the rule?\r
\n" ); document.write( "\n" ); document.write( "(In =x and out = answer)
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Algebra.Com's Answer #115416 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Use the two-point form of a straight line against two of the points and then test the other point against the rule you develop to see if the three given points are colinear.\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=%28%28y%5B1%5D-y%5B2%5D%29%2F%28x%5B1%5D-x%5B2%5D%29%29%28x-x%5B1%5D%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let \"P%5B1%5D\" be (5,3) and \"P%5B2%5D\" be (4,2.2)\r
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\n" ); document.write( "\n" ); document.write( "So \"y-3=%28%283-2.2%29%2F%285-4%29%29%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=0.8%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=0.8x-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=0.8x-1\" is your rule. Now check the other point:\r
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\n" ); document.write( "\n" ); document.write( "Does \"0.6=0.8%282%29-1\"? \"0.6=1.6-1\", \"0.6=0.6\" -- Yep.\r
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\n" ); document.write( "\n" ); document.write( "So your rule fits all three points and you are good to go.
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