document.write( "Question 156516This question is from textbook Geometry
\n" );
document.write( ": how do i find the perimeter and area of a rectangle in the coordinate plane:\r
\n" );
document.write( "\n" );
document.write( "L(0,1)M(3,5)N(5,5)P(5,1) \n" );
document.write( "
Algebra.Com's Answer #115405 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! I think instead of: \n" ); document.write( "L(0,1)M(3,5)N(5,5)P(5,1) \n" ); document.write( ". \n" ); document.write( "you meant: \n" ); document.write( "L(3,1)M(3,5)N(5,5)P(5,1) \n" ); document.write( ". \n" ); document.write( "It would be best to plot all four points onto graph paper. Once you do that, it will be easy to see that: \n" ); document.write( "width of the rectangle is between either: \n" ); document.write( "LP or MN \n" ); document.write( ". \n" ); document.write( "whereas the length of the rectangle is between either: \n" ); document.write( "LM or PN \n" ); document.write( ". \n" ); document.write( "Calculating the width. Let's use:M and N \n" ); document.write( "M(3,5)N(5,5) \n" ); document.write( "You can either see the distance visually from the graph or use the distance formula: \n" ); document.write( "distance = sqrt[(x2-x1)^2 + (y2-y1)^2] \n" ); document.write( "distance = sqrt[(5-3)^2 + (5-5)^2] \n" ); document.write( "distance = sqrt[(2)^2 + (0)^2] \n" ); document.write( "distance = sqrt[4 + 0] \n" ); document.write( "distance = sqrt[4] \n" ); document.write( "distance = 2 (width) \n" ); document.write( ". \n" ); document.write( "Calculating the length. Let's use:P and N \n" ); document.write( "P(5,1)N(5,5) \n" ); document.write( "You can either see the distance visually from the graph or use the distance formula: \n" ); document.write( "distance = sqrt[(x2-x1)^2 + (y2-y1)^2] \n" ); document.write( "distance = sqrt[(5-5)^2 + (5-1)^2] \n" ); document.write( "distance = sqrt[(0)^2 + (4)^2] \n" ); document.write( "distance = sqrt[0 + 16] \n" ); document.write( "distance = sqrt[16] \n" ); document.write( "distance = 4 (length) \n" ); document.write( ". \n" ); document.write( "Perimeter = 2(w+l) = 2(2+4) = 2(6) = 12 units \n" ); document.write( "area = wl = 2(4) = 8 square units\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |