document.write( "Question 156507: A moving van leaves the house traveling at an average rate of 35 mi/h. The family leaves the house 3/4 hour later following the same route in a car. They travel at an average rate of 50 mi/h.\r
\n" ); document.write( "\n" ); document.write( "a. write an expression for the time traveled by the car.
\n" ); document.write( "b. copy and complete this table:
\n" ); document.write( " moving van - rate: _____ time:_____ distance traveled: _____
\n" ); document.write( " car rate: _____ time:_____ distance traveled: _____
\n" ); document.write( "c. write and solve an equation to find out how long it will take the car to catch up with the moving van.
\n" ); document.write( "

Algebra.Com's Answer #115392 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
moving van - rate: 35 mi/hr time: t hr distance traveled: 35t mi
\n" ); document.write( " car - rate: 50 mi/hr time: (t - .75) hr dist traveled: 50*(t - .75)mi
\n" ); document.write( "When they meet, the distance each has travelled will be the same
\n" ); document.write( "\"d+=+35t\"
\n" ); document.write( "\"d+=+50%2A%28t+-+.75%29\"
\n" ); document.write( "\"35t+=+50%2A%28t+-+.75%29\"
\n" ); document.write( "\"35t+=+50t+-+37.5\"
\n" ); document.write( "\"15t+=+37.5\"
\n" ); document.write( "\"t+=+2.5\"hr (note: this is the time expired from when
\n" ); document.write( "the van left until it meets the car)
\n" ); document.write( "\"t+-+.75+=+1.75\"hr This is the time expired from when the car left
\n" ); document.write( "until it meets the van
\n" ); document.write( "So, the car will catch up with the van in 1 hr and 45 minutes
\n" ); document.write( "check:
\n" ); document.write( "\"d+=+35t\"
\n" ); document.write( "\"d+=+35%2A2.5\"
\n" ); document.write( "\"d+=+87.5\"mi
\n" ); document.write( "and
\n" ); document.write( "\"d+=+50%2A%28t+-+.75%29\"
\n" ); document.write( "\"d+=+50%2A1.75\"
\n" ); document.write( "\"d+=+87.5\"mi
\n" ); document.write( "OK
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