document.write( "Question 156507: A moving van leaves the house traveling at an average rate of 35 mi/h. The family leaves the house 3/4 hour later following the same route in a car. They travel at an average rate of 50 mi/h.\r
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document.write( "a. write an expression for the time traveled by the car.
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document.write( "b. copy and complete this table:
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document.write( " moving van - rate: _____ time:_____ distance traveled: _____
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document.write( " car rate: _____ time:_____ distance traveled: _____
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document.write( "c. write and solve an equation to find out how long it will take the car to catch up with the moving van. \n" );
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Algebra.Com's Answer #115392 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! moving van - rate: 35 mi/hr time: t hr distance traveled: 35t mi \n" ); document.write( " car - rate: 50 mi/hr time: (t - .75) hr dist traveled: 50*(t - .75)mi \n" ); document.write( "When they meet, the distance each has travelled will be the same \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "the van left until it meets the car) \n" ); document.write( " \n" ); document.write( "until it meets the van \n" ); document.write( "So, the car will catch up with the van in 1 hr and 45 minutes \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |