document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156564>Question 156564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Division by inspection<BR>\n" );
document.write( "Please help me solve the following problem:\r<BR>\n" );
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document.write( "27 a(cubed) + b(cubed) divided by 3a+b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115371 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 27 a(cubed) + b(cubed) divided by 3a+b\r<BR>\n" );
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document.write( "= [(3a)^3 + b^3] / [3a+b]<BR>\n" );
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document.write( "You have \"a difference of cubes.<BR>\n" );
document.write( "That factors as (3a+b)((3a)^2 -(3a)b+b^2)<BR>\n" );
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document.write( "The 3a+b factors in the numerator and in the denominator cancel and you get:<BR>\n" );
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document.write( "= (3a)^2 - (3a)b + b^2\r<BR>\n" );
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document.write( "= 9a^2 - 3ab + b^2<BR>\n" );
document.write( "========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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