document.write( "Question 156527: What quantity of 70 per cent acid solution must be mixed with a 20 percent solution to produce 700 mL of a 50 per cent solution? \n" ); document.write( "
Algebra.Com's Answer #115355 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .7X+.2(700-X)=.5*700 \n" ); document.write( ".7X+140-.2X=350 \n" ); document.write( ".5X=350-140 \n" ); document.write( ".5X=210 \n" ); document.write( "X=210/.5 \n" ); document.write( "X=420 mL OF 70% IS USED. \n" ); document.write( "700-420=280 mL of 20% is used. \n" ); document.write( "Proof: \n" ); document.write( ".7*420+.2*280=.5*700 \n" ); document.write( "294+56=350 \n" ); document.write( "350=350 \n" ); document.write( " \n" ); document.write( " |