document.write( "Question 156527: What quantity of 70 per cent acid solution must be mixed with a 20 percent solution to produce 700 mL of a 50 per cent solution? \n" ); document.write( "
Algebra.Com's Answer #115355 by checkley77(12844)\"\" \"About 
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.7X+.2(700-X)=.5*700
\n" ); document.write( ".7X+140-.2X=350
\n" ); document.write( ".5X=350-140
\n" ); document.write( ".5X=210
\n" ); document.write( "X=210/.5
\n" ); document.write( "X=420 mL OF 70% IS USED.
\n" ); document.write( "700-420=280 mL of 20% is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".7*420+.2*280=.5*700
\n" ); document.write( "294+56=350
\n" ); document.write( "350=350
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